Calculate the kinetic energy of a 100.0-kg meteor approaching the Earth at a speed of 10.0 km/s.

Remember that 1 km = 1000 m.

Kinetic Energy = (1/2) (mass) (speed squared)
Mass = 100 kg Speed = 10 km/s = 10,000 m/s Speed squared = 100,000,000 m²/s²
1/2 (M)(V²) = 1/2 (100) (100,000,000) = 5,000,000,000 joules (5 x 10⁹ J)
That's 5 billion joules.
That's the amount of energy a 100-watt light bulb uses in 579 days.

Answered by AL2006 | 2024-06-10

KE=1/2 x mass x speed^2 Substitute:
KE=1/2 x 100 x 10000^2 5000000000J of KE So either 5 gigajoules Or 5x10^9J

Answered by TaylorBayley | 2024-06-10

The kinetic energy of a 100.0-kg meteor approaching Earth at a speed of 10.0 km/s is calculated to be 5 billion joules (5 x 10⁹ J). This value is derived using the formula for kinetic energy, incorporating the mass and the speed of the meteor converted into meters per second. Such energy is vast, showing the immense impact potential of meteors.
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Answered by AL2006 | 2024-09-26