A student who weighs 500 newtons climbed the stairs from the first floor to the third floor, 15 meters above, in 20 seconds. How much work did she do?

Work = (500N)(15m)=7500J Power= (7500J)/(20s) =375 W
Hopefully this helps ;

Answered by kaitywazhere101202 | 2024-06-12

Well, the 20 seconds gives us enough information to actually calculate the power she has on her feet :) Well, the work is 500*15=7500J, that is 7.5 kJ or about 18 calories (1 cal is 418J?) The power is that 7.5 kJ divided by 20 seconds: 375W. That's... OK, I suppose...

Answered by Anonymous | 2024-06-24

The student did 7500 joules of work while climbing from the first floor to the third floor. This can also be expressed as 7.5 kilojoules. The work is calculated using the formula W = F × d, where F is her weight and d is the distance climbed.
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Answered by Anonymous | 2024-09-27