Do you think the buoyant force would be greater or smaller if the gold cube were suspended in water? Explain your answer.
Answer (3)
The buoyant force on a gold cube suspended in water would be the same as when it is fully submerged because the volume of displaced fluid remains constant, as per Archimedes' principle. ;
The buoyant force on an object submerged in a fluid is determined by the weight of the fluid displaced by the object. This is known as Archimedes' Principle. If a gold cube is suspended in water, the buoyant force acting on it would be equal to the weight of the water displaced by the cube. Assuming the cube is completely submerged and not touching the bottom or sides of the container, this force would not change whether the cube is resting at the bottom or suspended in the fluid. However, if the cube is on the bottom of the container, it is not purely experiencing the buoyant force but also the normal force from the solid container surface.
When the gold cube is suspended in the fluid, the only force acting upward is the buoyant force. The magnitude of this buoyant force can be observed by the fact that when the cube is removed, the space it occupied would be filled with fluid weighing the same as the displaced water. This concept explains why objects feel lighter in the water and why there is a net upward, or buoyant, force on submerged objects in a fluid.
The buoyant force on a gold cube suspended in water will be the same as when it is fully submerged, according to Archimedes' Principle. This is because the volume of water displaced remains constant regardless of whether the cube is submerged or suspended. Only changes in the cube's volume or the water's density would affect the buoyant force.
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