A box is lowered using a rope. If the acceleration of the box is 2.5 m/s\(^2\) (downward) and the tension in the rope is 31 N, what is the mass of the box (in kg)?

F= ma 31-mg = m(-2.5m/s2) 31= mg-2.5 m 31 = m*(9.8m/s2 -2.5 m/s2) 31 = 7.3 m m = 31/7.3 m = 4.25 kg

Answered by y7gm7g | 2024-06-10

To find the mass of the box, we use the formula T = m × (g - a), where 'T' represents tension, 'g' represents gravity, 'a' represents acceleration , and 'm' represents mass. We rearrange this to find 'm' as T / (g - a). The mass of the box is 4.56 kg (rounded to two decimal places). ;

Answered by Qwseed | 2024-06-18

The mass of the box being lowered is approximately 4.25 kg, calculated using Newton's second law by analyzing the tension and the downward acceleration. The formula used is m = g − a T ​ .
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Answered by Qwseed | 2024-12-26