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In Physics / High School | 2014-02-12

A space probe has two engines. Each generates the same amount of force when fired, and the directions of these forces can be independently adjusted. When the engines are fired simultaneously and each applies its force in the same direction, the probe, starting from rest, takes 24.8 s to travel a certain distance.

How long does it take to travel the same distance, again starting from rest, if the engines are fired simultaneously and the forces that they apply to the probe are perpendicular?

Asked by jazline2004

Answer (3)

it depends on what your reference point is...if want the distance perpendicular to the starting point in the plane, that's double the time (as only one motor is working perpendicular to the starting plane - 49.6), but if you are considering the whole distance (the diagonal distance), then, the probe would travel the same distance in @24.8*sqrt(2).

Answered by CChrisys | 2024-06-10

I would say around 5/4ths the time..
So, 31s
pls mark brainliest

Answered by qurataz | 2024-06-12

When the engines of the space probe fire in the same direction, it takes 24.8 seconds to reach a certain distance. If they fire perpendicularly, the acceleration will be greater due to the resultant force, allowing the probe to cover the same distance in approximately 17.55 seconds. Hence, firing perpendicularly results in a shorter travel time.
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Answered by qurataz | 2024-09-30