Write a pair of numbers such that the value of the 7 in the first number is 1000 times the value of the 7 in the second number, and the value of the 3 in the first number is 100 times the value of the 3 in the second number.
Answer (3)
If I get it right, then we could find for example those pairs of numbers:
7 0 3 00 vs 100 73 37 000 vs 10 3 0 7 7 000 3 000 vs 100 7 00 3 3 0 7 0000 vs 10 3 00 7 0
37 0000 vs 10 3 0 7 0
Answer-
As infinitely many such possible number pairs can be formed, one of the instances of such pair would be (37000 and 307).
Solution-
Suppose the former one is aaaaa and the later one is bbbbb.
The value of 7 in the former is 1000 times greater than in the later, so let's make it 7000 and 7.
Then the numbers will be in the following form,
a7aaa and bbbb7
Again, the value of 3 in the former is 100 times greater than in the later.
Then the numbers will be in the following form,
37aaa and bb3bb7
Substituting all the a's and b's by 0,
we get, 37000 and 307 is a possible set. Replacing 0 with any number from 1-9, will yield another number pair which will satisfy the conditions.
The answer includes pairs of numbers such as 37000 and 307, where the value of the digit '7' in 37000 is 1000 times that in 307, and the value of '3' in 37000 is 100 times that in 307. This is established by the positional values of the digits in each number. Thus, the solution meets the problem's requirements.
;
