Carlos pushes a 3 kg box with a force of 9 newtons. The force of friction on the box is 3 newtons in the opposite direction.
What is the acceleration of the box?
Answer (3)
friction = 3 N pushing force= 9 N as both are opposite in direction so their net force will be = 9-3= 6N as we know that F = ma re arranging the equation a = F/m by putting values a = 6/3 N/kg a= 2 m/sec ²
The 'net' force acting on the box is (9 - 3) = 6 newtons in the direction that Carlos is pushing.
Force = (mass) x (acceleration)
6 = (3) x (acceleration)
Divide each side by 3 :
2 m/s² = acceleration
The acceleration of the box is 2 m/s² in the direction that Carlos is pushing. This was calculated by determining the net force acting on the box and applying Newton's Second Law. The net force was found to be 6 N after accounting for friction.
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