Solve for \( Y \).

1. \( 2Y + 5x - z = 4y + 6x \)

2. \( 8xy = z \)

2 y + 5 x − z = 4 y + 6 x ∣ s u b t r a c t 4 y f ro m b o t h s i d es − 2 y + 5 x − z = 6 x ∣ s u b t r a c t 5 x f ro m b o t h s i d es − 2 y − z = x ∣ a dd z t o b o t h s i d es − 2 y = x + z ∣ d i v i d e b o t h s i d es b y ( − 2 ) y = − 2 x + z ​ ​ ============================== 8 x y = z ∣ d i v i d e b o t h s i d es b y 8 x y = 8 x z ​ ​

Answered by Anonymous | 2024-06-10

2y+5x-z=4y+6x
4y-2y=5x-6x-z
2y=-x-z
y=(-x-z)/2 **
------------------------ **
8xy=z
y=z/(8x) **
**

Answered by Anonymous | 2024-06-10

To solve for Y , first rearrange the first equation to isolate it, giving Y = 2 y + 2 x + z ​ . For the second equation, divide by 8 x to find y = 8 x z ​ . Both results provide different perspectives on the variable relationships.
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Answered by Anonymous | 2024-12-26