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In Physics / High School | 2014-09-06

1) An airplane starts from rest and accelerates at a constant [tex]3.00 \, \text{m/s}^2[/tex] for 30.0 s before leaving the ground. What is its displacement during this time?

Asked by Ruthy1212

Answer (2)

s=1/2at²+v(initial)t s=1/2(3)(30)²+(0)(30) s=1/2(3)(30)²+0 s=900(1/2)(3) s=450(3) s=1350m

Answered by Anonymous | 2024-06-10

The displacement of the airplane during the 30.0 seconds of acceleration is 1350 meters, calculated using the formula for displacement under constant acceleration from rest. By substituting the known values into the formula, we find that the airplane travels 1350 meters down the runway before takeoff.
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Answered by Anonymous | 2024-09-04

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