The mass of a subway car and its passengers is 40,000 kg. If its acceleration as it leaves the station is 0.9 m/s², what is the net force acting on it?

To answer this problem, we have to employ Newton's Second Law of Motion, or F = ma. F is the force in Newtons (N) where as m is mass (kg) and a is the acceleration (m/s^2). An easy plug in will give us
F = ma F = (40,000 kg.)(0.9 m/s^2) F = 36,000 N.
The answer is 36,000 N. Good luck!

Answered by cxcharlie | 2024-06-10

The net force acting on the subway car and it's passengers is 3.6 × 10⁴ Newton.
Given the data in the question;

Mass of a subway car and it's passengers; m = 40000 k g

Acceleration as it leaves the station; a = 0.9 m / s 2


Net force; F = ?
From Newton's second law of Motion:
F = m ∗ a
Where F is the force , m is mass of object and a is the acceleration.
We substitute our given values into the equation
F = 40000 k g ∗ 0.9 m / s 2 F = 36000 k g . m / s 2 F = 3.6 ∗ 1 0 4 N
Therefore, the net force acting on the subway car and it's passengers is 3.6 × 10⁴ Newton.
Learn more: https://brainly.com/question/13440504

Answered by nuhulawal20 | 2024-06-15

The net force acting on the subway car and its passengers is 36,000 Newtons (N), calculated using Newton's Second Law. This is achieved by multiplying the mass of the subway car (40,000 kg) by its acceleration (0.9 m/s²). Thus, the formula used is F = m × a, resulting in F = 36,000 N.
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Answered by nuhulawal20 | 2024-09-06