A 1.8 kg object moves in the x direction according to the following function:

\[ x(t) = 2t^2 + 3t - 5 \]

(SI units). What is the force on the object after 2.7 s?

Well, if the position is x(t) = 2t² + 3t - 5
then the speed is x ' (t) = 4t + 3 (first derivative of 'x' wrt 't')
and the acceleration is x ' ' (t) = 4 (second derivative of 'x' wrt 't')
Apparently, then, the acceleration is constant, and is not a function of time.
After 2.7 seconds or 2.7 years, the acceleration is 4 .
Force = (mass) x (acceleration)
Force = (1.8) x (4)
***Force = 7.2 newtons ***

Answered by AL2006 | 2024-06-10

The force on the object after 2.7 seconds is calculated to be 7.2 newtons. This is determined using the object's constant acceleration from its position function. The acceleration is found to be 4 m/s², and using Newton's second law, we include the mass to find the force.
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Answered by AL2006 | 2025-05-16