Starting at a certain speed, a bicyclist travels 200 m. Suppose the bicyclist undergoes a constant acceleration of 1.20 m/s\(^2\). If the final speed is 25.0 m/s, what was the bicyclist's initial speed?
Answer (2)
V2^2 = V1^2 + 2 a s V2 = final velocity V1 = initial velocity a = acceleration s = displacement covered 25^2 = V1^2 + 2 * 1.2 * 200 625 = V1^2 + 480 625 - 480 = V1^2 145 = V1^2 So V1 = Sqrt(145) = 12.04 m/s
The initial speed of the bicyclist was approximately 12.04 m/s, calculated using the kinematic equation involving final speed, acceleration, and distance traveled. This was derived by rearranging the equation to solve for initial velocity. By substituting the known values into the equation, we found the result step-by-step.
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