A cart rolling down an incline for 5.0 seconds has an acceleration of [tex]4.0 \, \text{m/s}^2[/tex]. If the cart has a beginning speed of [tex]2.0 \, \text{m/s}[/tex], what is its final speed?
Answer (2)
The final speed of the cart after 5.0 seconds, with an initial speed of 2.0 m/s and an acceleration of 4.0 m/s^2, is 22.0 m/s.
The question involves calculating the final speed of a cart rolling down an incline with a known acceleration and initial speed. To find the final speed, we can use the kinematic equation which relates acceleration, initial speed, and final speed over a time interval:
v = u + at
Where: v is the final speed, u is the initial speed (2.0 m/s), a is the acceleration (4.0 m/s2), t is the time (5.0 seconds).
Substituting our values in:
v = 2.0 m/s + (4.0 x 5.0 )
v = 2.0 m/s + 20.0 m/s
v = 22.0 m/s
Therefore, the final speed of the cart after 5.0 seconds is 22.0 m/s.
The final speed of the cart after rolling down the incline for 5.0 seconds with an initial speed of 2.0 m/s and an acceleration of 4.0 m/s² is 22.0 m/s. This is calculated using the kinematic equation v = u + at. By substituting the values, we find the final speed to be 22.0 m/s.
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