In my carpenter shop, I make 3-legged stools and 4-legged chairs. I looked at my day's output and counted 55 legs and 16 seats. How many stools and how many chairs did I complete that day?

x − n u mb er o f s t oo l s y − n u mb er o f c hai rs { 3 x + 4 y = 55 y + x = 16 ​ F ro m f i rs t e q u a t i o n : y = 16 − x S u b s t r a c t t o seco n d e q u a t i o n : 3 x + 4 ( 16 − x ) = 55 3 x + 64 − 4 x = 55 3 x − 4 x = 55 − 64 − x = − 9 x = 9 y = 16 − 9 = 7 { x = 9 y = 7 ​

Answered by luana | 2024-06-10

The student's carpenter shop produced 9 three-legged stools and 7 four-legged chairs, which was determined by solving a system of two equations. ;

Answered by srangoli003 | 2024-06-18

The carpenter completed 9 stools and 7 chairs, resulting from solving a system of equations based on the counts of legs and seats. The equations set up were for the total seats and total legs. By substitution and solving, we found the number of each item produced.
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Answered by luana | 2024-12-18