1 m ∗ 0.5 m = 0.5 m 2 g = 10 s 2 m 300 k g ∗ 10 s 2 m = 3000 N 3000 N − − 0.5 m 2 x − − 1 x = 6000 P a = 60 k P a
The pressure that the bookcase exerts on the floor is approximately 5.89 kPa. This was calculated by first determining the weight of the bookcase and then dividing that by the area of its base. Using the formulas for force and pressure allowed us to find the answer step-by-step.
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