The sum of three consecutive odd numbers is 153. What is the smallest of the three numbers?

a + a + 2 + a + 4 = 153 3 a + 6 = 153 3 a = 153 − 6 3 a = 147 a = 3 147 ​ = 49 − \ t h e s ma ll es t ​ a + 2 = 49 + 2 = 51 a + 4 = 49 + 4 = 53

Answered by mariamikayla | 2024-06-10

n + ( n + 2 ) + ( n + 4 ) = 153 -- combine like terms 3 n + 6 = 153 -- subtract 6 from both sides 3 n = 147 -- divide by 3 n = 49
So the numbers are 49, (49+2) and (49+4) I.e. 49, 51, and 53 But the question only wants the smallest (i.e. the first of the consecutive odd numbers). **
** The smallest of the 3 consecutive odd numbers that sum to 153 is 49

Answered by TaylorBayley | 2024-06-10

The smallest of the three consecutive odd numbers that sum to 153 is 49. The other two numbers are 51 and 53. Therefore, the three consecutive odd numbers are 49, 51, and 53.
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Answered by mariamikayla | 2024-09-09