A dragster traveling at 5 m/s north increases its velocity to 23 m/s north in 4 seconds. What is its acceleration during this time interval?

Acceleration = (change in speed) / (time for the change)
Acceleration = (23 - 5) m/s / 4s = 18/4 m/s² = 4.5 m/s²

Answered by AL2006 | 2024-06-10

To my recollection vf=vi+at 23m/s=5m/s + a (4s) get the like units together 23m/s - 5m/s = a (4s) 18m/s = a (4s) divide each side by 4 to find a 18m/s / 4s = 4.5m/s
I don't know how to do the up arrow to square any of the m/s.

Answered by evygirl | 2024-06-10

The acceleration of the dragster is calculated using the change in velocity over time. The result is an acceleration of 4.5 m/s² to the north. This value indicates how quickly the dragster increases its speed in that direction.
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Answered by AL2006 | 2024-12-26