The sum of three consecutive numbers is one hundred forty-four. What is the smallest of the three numbers?

n; n + 1; n + 2 - three consecutive numbers
n + (n + 1) + (n + 2) = 144 3n + 3 = 144 |subtract 3 from both sides 3n = 141 |divide both sides by 3
n = 47 - the smallest of the three numbers

Answered by Anonymous | 2024-06-10

The smallest of the three consecutive numbers that sum to 144 is 47. This is determined by defining the numbers as n, n+1, and n+2, leading to the equation 3n + 3 = 144. By solving for n, we find that n = 47.
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Answered by Anonymous | 2024-12-26