An amusement park line is moving about 4 feet every 15 minutes. At this rate, approximately how long will it take for a person at the back of the 50-foot line to reach the front of the line?

If the line is moving about 4 feet every 15 minutes, then a person will need about 3 hours to reach 50-foot line from the back to the front. It's because:
50 / 4 = 12,5 (that's how many quarters of an hour one needs to move 50 feet) 12,5 * 15 = 187,5 (that's how long it will take in minutes)
187,5 min = 3h 7min 30 sec
Approx. - 3h

Answered by SlowZasob | 2024-06-10

set it up in fractions and cross multiply:
15/4=x/50
4x=750
x=187.5 minutes which converts to 3.125
Your answer is 3 hours (:

Answered by corajune99 | 2024-06-10

A person at the back of a 50-foot line will take approximately 3 hours and 7 minutes to reach the front. This is based on the line moving at a rate of 4 feet every 15 minutes. The calculation involves determining the speed and then calculating the total time based on the distance of the line.
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Answered by SlowZasob | 2024-10-30