Each square on Olivia's chessboard is 11 square centimeters. A chessboard has 8 squares on each side. To the nearest tenth, what is the width of Olivia's chessboard?
Answer (2)
The width of Olivia's chessboard is calculated by finding the square root of the area of one square and then multiplying it by the number of squares along one side. The square root of 11 square centimeters is approximately 3.317 cm, and since there are 8 squares on each side, the width is 3.317 cm x 8, which rounds to 26.5 cm to the nearest tenth.
To find the width of Olivia's chessboard, we first need to know the dimensions of a single square and then how many squares make up the width of the board. Since each square is 11 square centimeters in area and the area of a square is found by squaring the side length, we can calculate the side length of each square. A chessboard typically has 8 squares on each side.
To calculate the side length of a square, we take the square root of the area:
The square root of 11 cm2 is approximately 3.317 cm (since 3.3172 is approximately equal to 11).
The width of the chessboard can then be found by multiplying the side length of one square by the number of squares along one edge:
Width = Side length of one square x Number of squares = 3.317 cm x 8 = 26.536 cm
To the nearest tenth, the width of Olivia's chessboard is approximately 26.5 cm.
The width of Olivia's chessboard is approximately 26.5 cm when rounded to the nearest tenth, calculated by multiplying the side length of one square by the total number of squares along one side. The side length is derived from the area of 11 square centimeters. By taking the square root of the area and multiplying by 8, we find the total width.
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