What is the cross-sectional area of an object that experiences a stress of [tex]6,000 \, \text{N/m}^2[/tex] when a force of [tex]2,400 \, \text{newtons}[/tex] is applied to it?
Answer (2)
F or m u l a f or s t ress : s t ress = cross sec t i o n a re a o f o bj ec t a ppl i e d f orce f orce = 2400 N s t ress = 6000 m 2 N 6000 = cross sec t i o n 2400 6000 ∗ cross sec t i o n = 2400 ∣ D i v i d e b y 6000 cross sec t i o n = 0 , 4 m 2
The cross-sectional area of the object can be calculated using the stress formula, which is the ratio of applied force to the cross-sectional area. Given a stress of 6000 N/m² and an applied force of 2400 N, we find the cross-sectional area to be 0.4 m². Therefore, the answer is 0.4 m².
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