How many ways can 5 children line up to get on the school bus if Jenny always gets on third?

Normally, it would be 5x4x3x2x1; decreasing as the number of children decreases, from being in line. However, because Jenny is always third, it would be 4x3x1x2x1, or 24. There are 24 ways the children can line up if Jenny is always third in line.

Answered by Anonymous | 2024-06-10

There are 24 different ways the 5 children can line up for the bus with Jenny always in the third position. This is determined by fixing her position and calculating the permutations of the remaining 4 children, which is 4! or 24. Thus, the answer to the question is 24.
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Answered by Anonymous | 2024-12-26