Find four consecutive multiples of 5 whose sum is 90.

M₅+(M₅+5)+(M₅+10)+(M₅+15)=90
5M₅+ 30=90
5M₅=90-30
5M₅=60
M₅=60:5
M₅=12
M₅+5=12+5=17
M₅+10=12+10=22
M₅+15=12+15=27

Answered by mariamikayla | 2024-06-10

The four consecutive multiples of 5 that sum to 90 are 15, 20, 25, and 30. We set up an equation to find the first multiple and confirmed the calculation by summing the numbers. This verification shows that the solution is correct.
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Answered by mariamikayla | 2024-12-26