A race car starting from rest accelerates uniformly at [tex]4.9 \, \text{m/s}^2[/tex]. What is the car's speed after it has traveled 200 meters?
Answer (3)
The equation v²=u²+2as will help with solving this equation v is what we are trying to find u=0 a=4.9 s=200 v²=0²+2 4.9 200 v=√(2 4.9 200) v=√1960 v=44.3 m/s (3 sf)
Hello!
A race car starting from rest accelerates uniformly at a rate of 3.90 m/s² what is the cars speed after it has traveled 200 m.
We have the following data:
Vf (final velocity) = ? (in m/s)
Vi (initial velocity) = 0 m/s (accelerated from rest)
d (displacement) = 200 m
a (acceleration) = 4.90 m/s²
Since we do not need to know the time elapsed during the movement, we apply the data of the question to the Equation of Torricelli, let us see:
V f 2 = V i 2 + 2 ∗ a ∗ d
V f 2 = 0 2 + 2 ∗ 4.90 ∗ 200
V f 2 = 0 + 1960
V f 2 = 1960
V f = 1960
V f = 44.27188724...
V f ≈ 44.27 m / s ✓ ✓ ✓
I Hope this helps , greetings... Dexteright02 !
The speed of the race car after it has traveled 200 meters while accelerating uniformly at 4.9 m/s² is approximately 44.27 m/s. This is calculated using Torricelli's equation, which relates final velocity to initial velocity, acceleration, and distance traveled. Starting from rest, the car's initial velocity is 0, and after substituting the values into the equation, we find the final speed.
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