In Physics / High School | 2014-09-18

An object starts from rest and accelerates at [tex]4.3 \, \text{m/s}^2[/tex] for [tex]2.05[/tex] seconds. What is its displacement from the start position?

Asked by valenciobarron

Answer (1)

displacement = s = v1t +1/2at2 = 0 * 2.05 +1/2*(4.3)*(2.05^2) = 0 + 9.04 = 9.04 m

Answered by y7gm7g | 2024-06-10

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