A stone falls from the top of a 125 m high cliff.
How long does it take to reach the sea?
Given:
- Distance, [tex]S[/tex] = 125 m
- Acceleration, [tex]A[/tex] = 10 m/s²
To find the time, an additional piece of information such as the final velocity or initial velocity is needed.
Answer (3)
The initial velocity is 0 since it isn't moving at the beginning. 0=-10t^2+125 10t^2=125 t^2=12.5 t≈3.53553391 seconds
V1 = initial velocity = 0 ( fall = dropped= from rest ) S = V1*t + 1/2 g t^2 125 = 0 + 1/2 *10 t^2 = 5 t^2>>>>>>>>>>>>t^2 = 125/5 = 25 t = sqrt 25 = 5 sec V2 = final velocity = V11 + gt = 0 + 10 * 5 = 50m/s
The stone takes 5 seconds to reach the sea from a 125 m high cliff when dropped. This is calculated using the equation of motion for objects under constant acceleration due to gravity. The initial velocity is zero, and the acceleration is set to 10 m/s².
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