In the proportion \(\frac{2}{h} = \frac{k}{10}\), what happens to the value of \(h\) as the value of \(k\) decreases?

It increases as this is an example of inverse proportionality.

Answered by AndyBryer | 2024-06-10

If 2/h is equal to k/10 try substituting #s that would work in that situations. And then try changing them. And see what happens to the numbers.

Answered by cmongold65 | 2024-06-10

As the value of k decreases, the value of h increases due to their inverse proportional relationship. This means that lower values of k will result in higher values of h .
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Answered by AndyBryer | 2024-12-26