You throw a ball downward from a window at a speed of 2.0 m/s. How far has it fallen in 3 seconds?

Let's just assume that you throw the ball with an initial speed of 2 m/s instead of dropping it like free falling. a=9.81 m/s^2 Vi= 2 m/s t= 3 x
we use the formula d = (Vi)(t) + (1/2)(a)(t)^2 d= (2)(3) + (1/2)(9.81)(9) d=50.145 m

Answered by samuelhoang | 2024-06-10

After throwing the ball downward at 2.0 m/s for 3 seconds, it falls approximately 50.15 meters. This is calculated using the equations of motion considering both the initial speed and the acceleration due to gravity. The total distance fallen includes the contribution from both the initial velocity and gravitational acceleration.
;

Answered by Anonymous | 2025-02-19