Solve for \( h \):

\[ \frac{2}{5}h - 7 = \frac{12}{5}h - 2h + 3 \]

5 h − 7 2 ​ = 5 h − 2 h + 3 12 ​ 5 h − 7 2 ​ = 3 h + 3 12 ​ 2 ( 3 h + 3 ) = 12 ( 5 h − 7 ) 6 h + 6 = 60 h − 84 6 h − 60 h = − 84 − 6 − 54 h = − 90 h = − 54 − 90 ​ = 9 15 ​ = 3 5 ​ ​

Answered by mariamikayla | 2024-06-10

5 2 ​ h − 7 = 5 12 ​ h − 2 h + 3 ∣ M u lt i pl y b y 5 2 h − 35 = 12 h − 10 h + 15 2 h − 35 = 2 h + 15 ∣ S u b t r a c t 2 h − 35  = 15 T h ere a re n o so l u t i o n s .

Answered by luana | 2024-06-10

The equation 5 2 ​ h − 7 = 5 12 ​ h − 2 h + 3 simplifies to a contradiction, indicating that there are no values of h that satisfy it. This means the equation has no solution. h cannot take any real number value to make this equation true.
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Answered by mariamikayla | 2024-10-01