Solve for \( p \).

\[ 8 (4p + 1) = 32p + 8 \]

8 ( 4 p + 1 ) = 32 p + 8 32 p + 8 = 32 + 8 32 p − 32 p = 8 − 8 0 = 0 ​ A n s w er : p c an t ak e an y v a l u e b ec a u se e v ery n u mb er w o u l d mak e t h e se n t e n ce t r u e .

Answered by mariamikayla | 2024-06-10

What is your question ? Are you asking for the solution of the equation ?
The "solution" is the number that 'p' must be, in order to make the equation a true statement.
When you eliminate the parentheses on the left side of the equation, the left side becomes 32p + 8 .
Then the equation says 32p + 8 = 32p + 8 .
That's a true statement no matter what 'p' is .
So any number and every number is a solution of the equation.

Answered by AL2006 | 2024-06-10

The equation 8 ( 4 p + 1 ) = 32 p + 8 simplifies to 8 = 8 , which is always true. Therefore, p can take any value, indicating infinitely many solutions. This is known as an identity in mathematics.
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Answered by mariamikayla | 2024-09-05