How far will a freely falling object fall from rest in six seconds?

Tabulate, then find the proper equation, then solve.
vi=0 vf=? t=6s a=g=9.8m/s²
vf=vi+at vf=gt vf= (find this yourself)

Answered by schuhplattler42 | 2024-06-10

To determine how far a freely falling object will fall from rest in six seconds, we use the equation of motion for an object under constant acceleration due to gravity. The equation is s = ut + ½at² where:

s is the distance fallen,
u is the initial velocity (which is 0 m/s since the object is falling from rest),
a is the acceleration due to gravity (9.8 m/s²), and
t is the time in seconds.

Substituting the known values into the equation gives us:
s = 0 × 6 + ½ × 9.8 m/s² × 6²
s = ½ × 9.8 m/s² × 36
s = 4.9 m/s² × 36
s = 176.4 m
The object will fall a distance of 176.4 meters in six seconds when dropped from rest, assuming there is no air resistance.

Answered by ZeldaWilliams | 2024-06-24

In six seconds, a freely falling object will drop 176.4 meters from rest due to the acceleration of gravity. This is calculated using the motion equation with an initial velocity of zero and an acceleration of 9.8 m/s². Therefore, the distance fallen can be derived as 176.4 meters.
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Answered by ZeldaWilliams | 2024-09-05