A = 32 f t 2 A = 2 b ∗ h 2 b ∗ 4 = 32 b = 4 2 ∗ 32 b = 2 ∗ 8 b = 16 f t
F or m u l a f or a re a o f t r ian g l e : A re a = 2 1 ba se ∗ h e i g h t 32 = 2 1 ∗ 4 ∗ ba se 32 = 2 ba se ∣ D i v i d e b y 2 ba se = 16 f t L e n g t h o f ba se i s e q u a l t o 16 f t .
The length of the base of the triangle is 16 ft. This is calculated using the area formula for triangles. By rearranging the formula, we can solve for the base given the area and height.
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