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In Mathematics / Middle School | 2014-09-24

Marcus, Sally, and Sammy decided to share 20 sweets. Marcus took 8 sweets, and Sally took three times as many as Sammy. How many sweets did Sammy receive?

Asked by allyandtodd

Answer (3)

x − am o u n t o f s w ee t s w hi c h S amm y t oo k 3 x − am o u n t o f s w ee t s w hi c h S a ll y t oo k 3 x + x + 8 = 20 4 x + 8 = 20 ∣ S u b t r a c t 8 4 x = 12 ∣ D i v i d e b y 4 x = 3 S am y rece i v e d 3 s w ee t s .

Answered by luana | 2024-06-10

Hello,
they decided to share 20 sweets, but Marcus took 8 sweets, so:
20-8=12
We have 12 sweets left.
x= number of sweets that Sally took y= number of sweets that Sammy took
We know that Sally took three times as many as Sammy, so: x=3y
There are 12 sweets:
x+y=12
Replacing x:
3y+y=12 4y=12 y=3
x=3*(3) x=9
Answer: Sally took 9 sweets and Sammy 3

Answered by Illuminati750 | 2024-06-10

Sammy received 3 sweets. This is calculated by setting variables for the number of sweets each person took and solving a simple equation. Verifying with the total leads to the same result.
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Answered by luana | 2025-02-15