A boulder on the mythical planet Mongo drops off a cliff and falls from rest 1000 m in 10.0 s.

(A) What is the initial speed of the boulder?

(B) Determine the acceleration due to gravity on Mongo. Ignore friction.

at rest, initial speed zero
x=v(initial) t+ 1/2 at^2 -1000m=0(10) + 1/2 a 10^2 -1000m=50a a = -20 m/s^2

Answered by ody75 | 2024-06-10

The student's question involves a boulder falling off a cliff on a mythical planet and requires us to find the initial speed and the acceleration due to gravity. Starting with (A) the initial speed of the boulder, we know that the boulder begins from rest, which means the initial velocity is 0 m/s.
For (B) determining the acceleration due to gravity on planet Mongo, we can use the kinematic equation for freely falling objects:
s = ut + 0.5at²
where:
s is the displacement (1000 m)
u is the initial velocity (0 m/s, since it starts from rest)
a is the acceleration due to gravity, which we need to find
t is the time the boulder was falling (10.0 s)
Plugging the known values into the equation, we have:
1000 m = 0 m/s * 10.0 s + 0.5 * a * (10.0 s)²
From the equation, we can solve for a:
a = (2 * 1000 m) / (10.0 s)² = 20 m/s²
Therefore, the acceleration due to gravity on planet Mongo is 20 m/s²

Answered by DestinyHopeCyrus | 2024-06-24

The initial speed of the boulder on Mongo is 0 m/s as it starts from rest. The acceleration due to gravity on Mongo is determined to be 20 m/s² using the kinematic equation. So, we find that the boulder accelerates downwards at a rate of 20 m/s² as it falls 1000 m in 10 seconds.
;

Answered by DestinyHopeCyrus | 2024-12-26