When striking, the pike, a predatory fish, can accelerate from rest to a speed of [tex]4.0 \, \text{m/s}[/tex] in [tex]0.11 \, \text{s}[/tex].

How far does the pike move during its strike?

(Note: Part A's answer is [tex]36.36\ldots[/tex] repeating)

In an uniform accelerated motion, the distance covered by the fish is given by: S = 2 1 ​ a t 2 where a is the acceleration t is the time
The acceleration is equal to the increase in speed of the fish divided by the time taken: a = t v f ​ − v i ​ ​ = 0.11 s 4 m / s − 0 m / s ​ = 36.4 m / s 2 If substitute the acceleration into the first equation, we find the distance covered by the fish: S = 2 1 ​ a t 2 = 2 1 ​ ( 36.4 m / s 2 ) ( 0.11 s ) 2 = 0.22 m

Answered by skyluke89 | 2024-06-11

To determine the distance a pike moves during its strike, we use the kinematic equation S = 0.5at^2. Given an acceleration of approximately 36.36 m/s^2 and a time of 0.11 s, the pike moves approximately 0.22 meters during the strike. ;

Answered by BetteDavis | 2024-06-18

The pike accelerates from rest to a speed of 4.0 m/s in 0.11 seconds, resulting in an acceleration of approximately 36.36 m/s². The distance traveled during this acceleration is about 0.22 meters (22.0 cm). Hence, the total distance the pike moves during its strike is 0.22 meters.
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Answered by skyluke89 | 2024-08-28