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In Physics / High School | 2014-09-24

A ball is dropped from the top of an 84-meter-high building. What speed does the ball have after falling for 3.6 seconds?

Asked by paulastewart90

Answer (3)

V2 = V1 + gt V2 = 0 + 9.8*3.6 = 35.28 m/s

Answered by y7gm7g | 2024-06-10

The speed of the ball when **falling **for 3.6 seconds is approximately 35.28m/s. ;

Answered by MarlonBrando | 2024-06-18

After falling for 3.6 seconds, the ball will have a speed of approximately 35.28 m/s. This is determined using the equation v = g t , where g is the acceleration due to gravity. This assumes no air resistance is affecting the ball's speed.
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Answered by MarlonBrando | 2025-01-26

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