Suppose \( y \) varies directly as \( x \), and \( y = 16 \) when \( x = 8 \). Find \( y \) when \( x = 16 \).

**The value of y for x = 16 is: **
y = 32 ; For this case, since the variation is direct then we have a relation of the form:
y = k x
Where,
k: proportionality constant
To find k we substitute the following data:
y = 16 when x = 8
We have then:
16 = k 8
Clearing the value of k we have:
[ k = \frac{16}{8}
k = 2 ]
Then, the equation is:
y = 2 x
Substituting the value of x = 16 we have:
[ y = 2 (16)
y = 32 ]

Answered by carlosego | 2024-06-24

y varies directly as x, and y =16 when x=8. Find y when x=16 **y is double x **
so when x=16 y=16x2 which equals 32

Answered by logo88 | 2024-06-24

When x = 16 , the value of y is 32. This is determined by the direct variation relationship established as y = 2 x . After substituting x = 16 into this equation, we find y .
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Answered by carlosego | 2024-09-26