Solve the following equations:

1. \(\frac{1}{2}\left(\frac{1}{3}w + 4\right) + 6 = 10\)

2. \(-5(h + 4) = 12\)

2 1 ​ ( 3 1 ​ w + 4 ) + 6 = 10 6 1 ​ w + 2 4 ​ + 6 = 10 6 1 ​ w + 2 + 6 = 10 6 1 ​ w + 8 = 10 ∣ S u b t r a c t 8 6 1 ​ w = 2 ∣ M u lt i pl y b y 6 w = 12 ​ − 5 ( h + 4 ) = 12 − 5 h − 20 = 12 ∣ A dd 20 − 5 h = 32 ∣ D i v i d e b y − 5 h = − 5 32 ​ = − 6 5 2 ​ h = − 6 5 2 ​ ​

Answered by luana | 2024-06-10

1/2(1/3w+4)+6=10 -5(h+4)=12 5/6w+2+6=10 -5h-20=12 5/6w+8=10 +20 +20 -8 -8 -5h=32 5/6w=2 -5h/5=32/5 ·6 ·6 h=32/5 5w=12 5w/5=12/5 w=12/5

Answered by nhallman2017 | 2024-06-10

The solution for the first equation is w = 12 and for the second equation is h = − 6 5 2 ​ . Each equation was solved by isolating the variable through step-by-step operations.
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Answered by luana | 2024-12-26