Hello!
The speed of a car is decreased uniformly from 30. meters per second to 10. meters per second in 4.0 seconds. What was the car's acceleration ?
We have the following data:
V (final velocity) = 10 m/s
Vo (initial velocity) = 30 m/s
ΔV (speed interval) = V - Vo → ΔV = 10 - 30 → ΔV = - 20 m/s
ΔT (time interval) = 4.0 seconds
a (average acceleration) = ? (in m/s²)
Formula:
a = Δ T Δ V
Solving:
a = Δ T Δ V
a = 4.0 s − 20 s m
a = − 5 s 2 m ✓
I Hope this helps , greetings... Dexteright02 !
Acceleration (magnitude anyway) = (change in speed) / (time for the change) .
Change in speed = (10 - 30) = -20 m/s
Time for the change = 4.0sec
Magnitude of acceleration = -20/4 = ***-5 m/s² ***
The car's acceleration is − 5 m/s 2 , indicating it is decelerating. This is calculated using the change in velocity over the time interval. The negative sign reflects that the speed of the car is decreasing.
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