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In Physics / High School | 2014-09-29

A boy throws a stone straight upward with an initial speed of 15 m/s. What maximum height will the stone reach before falling back down?

Asked by June15

Answer (3)

h e i g h t = 2 g r a v i t y v e l oc i t y 2 ​ v e l oc i t y = 15 s m ​ g = 9 , 8 s 2 m ​ h e i g h t = 2 ∗ 9 , 8 1 5 2 ​ = 19 , 6 225 ​ h e i g h t = 11 , 48 m e t ers ​

Answered by luana | 2024-06-10

The** maximum height** reached by the stone is approximately 11.5 meters. ;

Answered by Qwseed | 2024-06-18

The maximum height the stone will reach when thrown up at an initial speed of 15 m/s is approximately 11.48 meters. This is calculated using the formula h = 2 g v i 2 ​ ​ . The stone will reach this height before its speed decreases to zero due to gravity.
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Answered by luana | 2024-09-04

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