A bullet leaves a rifle with a muzzle velocity of 521 m/s. While accelerating through the barrel of the rifle, the bullet moves a distance of 0.840 m. Determine the acceleration of the bullet (assume a uniform acceleration).

v e l oc i t y = t im e d i s t an ce ​ v e l oc i t y ∗ t im e = d i s t an ce t im e = v e l oc i t y d i s t an ce ​ t im e = 521 s m ​ 0 , 840 m ​ = 0 , 0016 s a cce l er a t i o n = t im e v e l oc i t y ​ = 0 , 0016 521 ​ = 325625 s 2 m ​

Answered by luana | 2024-06-10

a = 1.62*105 m /s2 ;

Answered by gfgggdgd | 2024-06-16

The acceleration of the bullet as it moves through the barrel of the rifle is approximately 161,015 m/s². This is calculated using the final velocity, initial velocity, and distance traveled. Utilizing the equation of motion, we find that this high acceleration enables the bullet to reach its muzzle velocity quickly.
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Answered by gfgggdgd | 2024-10-01