If a 3.1 g ring is heated using 10.0 calories, and its temperature rises 17.9°C, calculate the specific heat capacity of the ring.

so what you do is you use the formula shown below:
specific heat capacity = energy required / (mass * change in temperature) here , energy required = 10.0°C Note that cal. is short form for °C mass (m) = 3.1g change in temperature (ΔT) = 17.9°C Note that "ΔT" means change in temperature
So, plugging the values into the formula, we get,
Specific heat capacity= 3.1 ∗ 17.9 10 ​
= 0.1802126509 = 0.1802 cal./g°C i rounded the answer to the fourth decimal point

Answered by rabinshrestha41 | 2024-06-10

The specific heat capacity of a 3.1g ring that is heated with 10.0 calories causing a temperature rise of 17.9°C is approximately 0.1801 cal/g°C. ;

Answered by JeanneReese | 2024-06-18

The specific heat capacity of the ring is approximately 0.1802 cal/(g °C), calculated using the formula c = m ⋅ Δ T Q ​ . This indicates how much energy is required to change the temperature of the material. Understanding specific heat is important in thermodynamics and material science.
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Answered by rabinshrestha41 | 2024-09-04