Ramiro is \(\frac{3}{10}\) as tall as a flagpole. The flagpole is \(\frac{5}{9}\) as tall as a nearby tree. The tree is \(32 \frac{2}{5}\) feet tall. How tall is Ramiro?
Answer (3)
32 2/5 = 162/5 162/9 = 18 18 x 5 = 90 90/10 = 9 9 x 3 = 27.
That makes Ramiro 27/5 feet tall or you can also say he's 5 2/5 feet tall.
Let
x---------> Ramiro's height
y--------> height of the flagpole
z-------> height of the tree
we know that
z = 32 5 2 z = ( 32 ∗ 5 + 2 ) /5 z = 5 162 f t
Find the height of the flagpole
y = 9 5 ∗ 5 162 y = 9 162 y = 18 f t
2) Find the height of Ramiro
x = 10 3 ∗ 18 x = 10 54 x = 5.4 f t x = 5 5 2 f t
therefore
the answer is
**The height of Ramiro is 5 5 2 f t **
Ramiro's height is 5 5 2 feet. This is calculated by first determining the height of a tree and then finding the heights of the flagpole and Ramiro based on their proportional relationships. The calculations involve simple arithmetic and fraction conversions.
;
