If an object accelerates from rest with a constant acceleration of [tex]5.4 \, \text{m/s}^2[/tex], what will its velocity be after 28 seconds?

"Acceleration of 5.4 m/s² " means that its speed increases by 5.4 m/s every second.
If it starts from zero, then after 28 sec its speed is (28 x 5.4) = 151.2 m/s .

Answered by AL2006 | 2024-06-10

The velocity of an object that accelerates from rest with a constant acceleration of 5.4 m/s² after 28 seconds will be 151.2 m/s, calculated using the formula v = u + at, with the initial velocity u being 0 m/s. ;

Answered by MilenaMarkovna | 2024-06-18

After 28 seconds of constant acceleration at 5.4 m/s 2 , the object's velocity will reach 151.2 m/s . This is calculated using the formula for final velocity under constant acceleration from rest. Plugging in the values gives us the result.
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Answered by AL2006 | 2024-10-09