v e l oc i t y f ina l − v e l oc i t y ini t ia l = t im e d i s t an ce v ini t ia l = 21 s m v f ina l = 0 s m t im e = 21 s Δ v ∗ t im e = d i s t an ce d i s t an ce = ∣ ( 0 − 21 ) ∗ 21∣ = 441 m B u s t r a v e l e d 441 m e t ers .
The bus travels a distance of 220.5 meters while slowing down from 21 m/s to a complete stop over 21 seconds. This is calculated by finding the average speed during the deceleration and multiplying it by the time. The average speed was determined to be 10.5 m/s.
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