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In Physics / High School | 2014-09-30

A bus slows down uniformly from 21 m/s to a complete stop in 21 seconds. How far did the bus travel before stopping?

Asked by Mmena6272

Answer (2)

v e l oc i t y f ina l ​ − v e l oc i t y ini t ia l ​ = t im e d i s t an ce ​ v ini t ia l ​ = 21 s m ​ v f ina l ​ = 0 s m ​ t im e = 21 s Δ v ∗ t im e = d i s t an ce d i s t an ce = ∣ ( 0 − 21 ) ∗ 21∣ = 441 m B u s t r a v e l e d 441 m e t ers .

Answered by luana | 2024-06-10

The bus travels a distance of 220.5 meters while slowing down from 21 m/s to a complete stop over 21 seconds. This is calculated by finding the average speed during the deceleration and multiplying it by the time. The average speed was determined to be 10.5 m/s.
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Answered by luana | 2024-10-01