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In Physics / Middle School | 2014-09-30

If you drop a silver dollar off a building and it hits the ground in 10 seconds, how fast was the coin going just before it hit the ground?

Asked by Unkown

Answer (3)

objects in free fall, disregarding terminal velocity, accelerate at 9.8(m/s)/s. so for every second it was falling, it gained 9.8m/s in speed. 9.8 * 10 =** 98m/s**

Answered by Anonymous | 2024-06-10

velocity = 9.8 x 10 velocity is 98 meters/second Velocity is speed

Answered by jonericfogg | 2024-06-10

The silver dollar will be traveling at a speed of 98 m/s just before it hits the ground after falling for 10 seconds. This is calculated using the acceleration due to gravity, which is 9.8 m/s². The formula used is v = g * t, where t is the time in seconds.
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Answered by Anonymous | 2024-09-05

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