At launch, the space shuttle weighs 4.5 million pounds. When it is launched from rest, it takes 8.00 seconds to reach 162 km/h, and at the end of the first 1.00 minute, its speed is 1620 km/h.
a) Assuming the acceleration is constant during each time interval (but not necessarily the same in both intervals), what distance does the shuttle travel during the interval from 8.00 seconds to 1.00 minute?
Answer (3)
dist = 162*t + A(accelaration) t^2/2 = 162 52+(((1620-162)/52) 52^2)/2 =162 52+((1620-162)*52)/2=46332kilometres
To find the distance the **space shuttle **traveled from the 8th second to the 1st minute of its journey, we calculated the distance for each time interval separately, converting speeds to m/s for simpler computation. For the first 8 seconds, the shuttle moved 360m, then we calculated the distance for the remaining 52 seconds. The total **distance traveled **is the sum of these two segments. ;
The distance traveled by the space shuttle from 8.00 seconds to 1.00 minute is approximately 12,978.1 meters. This was calculated by considering two intervals of motion and using the equations of motion to find the distance in each interval. The total distance is the sum of distances from both intervals.
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