How do you solve a problem like this:
How much force must Mr. McDonald exert to lift a 112 kg object?
What would happen if Mr. McDonald exerts more than the required force to lift the object?
Answer (3)
The weight of an object is (mass) x (gravity).
The weight of Mr. McDonald's object is (112) x (9.8) = 1,097.6 newtons .
(about 247 pounds)
That's the force pulling the object down, because it is near the Earth, and the Earth and the object are attracting each other with forces of gravity.
In order to move the object away from the center of the Earth ("lift" it), a force greater than 1,097.6 newtons must be applied to it in the other direction ... upwards .
Any force greater than its weight will lift it. The more the upward force exceeds the minimum of 1,097.6 newtons, the faster Mr. McDonald's object will accelerate upwards.
To solve the problem of calculating the force required to lift a 112 kg object, we can use Newton's second law of motion, which states that force (F) is equal to mass (m) multiplied by acceleration (a). In this case, since the object is being lifted vertically, the acceleration is equal to the acceleration due to gravity (9.8 m/s²).
So, the formula for calculating the force is F = m * a. Plugging in the values, we get F = 112 kg * 9.8 m/s² = 1097.6 N.
If Mr. McDonald exerts more force than the required 1097.6 N, the object would still experience the same acceleration due to gravity. However, if Mr. McDonald exerts less force, the object would not be lifted or would move at a slower rate.
Mr. McDonald must exert at least 1097.6 N to lift a 112 kg object. If he applies more force than this, the object will accelerate upwards faster. The relationship between force, mass, and acceleration is governed by Newton's laws of motion.
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