Vf=√30²+100² Vf=104 m/s
|Ф|=tan inverse of |100÷30| Ф= 73 degrees
Therefore the resulting velocity of the airplaine is 104 m/s [ 73 degrees N of W]
The resultant velocity of the airplane is 104.4 m/s. ;
The resultant velocity of the airplane is approximately 104.4 m/s, at an angle of 16.7° west of north. This is calculated using the Pythagorean theorem for vectors representing the airplane's speed and the crosswind. Thus, the overall motion of the airplane is slightly skewed to the west due to the wind.
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