A railway engine with a mass of 6000 kg is traveling at 4 m/s when it collides with and couples to a truck with a mass of 2000 kg that is not moving.

A. Calculate the momentum of the engine before the collision.

B. Show that the engine and the truck moved at a velocity of 3 m/s after the collision.

A) Momentum (p) = Mass (m) × Velocity ( v )
Initial momentum (p₀) = (6000 kg)(4 m/s) + (2000 kg)(0 m/s) = 24000 kg·m/s
B) Conservation of Momentum states that the initial momentum must equal the final momentum. Find velocity ( v ) after collision . . .
(6000 kg)(4 m/s) + (2000 kg)(0 m/s) = (6000 kg)( v m/s) + (2000 kg)( v m/s)
(6000)(4) + (2000)(0) = (6000) v + (2000) v
(24000) + (0) =(6000 + 2000)*v
24000 = 8000 v
*24000/8000 = *v
*24/8 = *v
*3 = *v
Thus:
v = 3 m/s *

Answered by Anonymous | 2024-06-10

The answer is A calculate the monumentum before the collision of the engine.

Answered by kinghomework | 2024-06-10

The momentum of the railway engine before the collision is 24000 kg·m/s. After applying the conservation of momentum, it is shown that the combined engine and truck move at a velocity of 3 m/s after the collision. This is calculated by equating the initial and final momentum of the system before and after the collision.
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Answered by Anonymous | 2024-10-15